Question

Neon has two isotopes ne 20 and ne 22 if atomic weight of neon is 20.2 the ratio of the relative abundances of the isotopes is

Answer 1

Answer:

Let % abundance of 20^Ne = x

" " " 22^Ne =100-x

Explanation:

M

$avg \: atm \: mas = \frac{M1p1 +M2p2}{100}$

$20.2 = \frac{20x + 22 (100-x)}{100} \\ 2020 = 20x + 2200 - 22x \\ 22x - 20x = 2200 - 2020 \\ 2x = 180 \\ x = 90$

%abundance of 20Ne = 90

%abundance of 22Ne =(100-90)=10%