Chemistry, asked by Kunal55677, 5 months ago

Nernst Equation at equilibrium only equation no details need ​

Answers

Answered by Anonymous
8

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\displaystyle\large\underline{\sf\purple{ Nernst\: Equation:- }}

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 \sf \: E_{cell}=E°_{cell}+\dfrac{-2.303RT}{nF}\log  \dfrac{[Prduct]}{[Reactant]}

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At Equlilbrum , \sf \: E_{cell}=0

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The Nernst Equation is modified as :-

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 \sf0=E°_{cell}+\dfrac{-2.303RT}{nF}log \dfrac{[Prduct] _{equilibrium}}{[Reactant] _{equilibrium}}

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 \sf \dashrightarrow  \: E°_{cell} = \dfrac{2.303RT}{nF}\log(k_{c})

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Kc= equilibrium constant at 298K

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