Chemistry, asked by Kunal55677, 6 months ago

Nernst Equation at equilibrium only equation no details need ​

Answers

Answered by Anonymous
8

 \\

\displaystyle\large\underline{\sf\purple{ Nernst\: Equation:- }}

 \\

 \sf \: E_{cell}=E°_{cell}+\dfrac{-2.303RT}{nF}\log  \dfrac{[Prduct]}{[Reactant]}

 \\

At Equlilbrum , \sf \: E_{cell}=0

 \\

The Nernst Equation is modified as :-

 \\

 \sf0=E°_{cell}+\dfrac{-2.303RT}{nF}log \dfrac{[Prduct] _{equilibrium}}{[Reactant] _{equilibrium}}

 \\

 \sf \dashrightarrow  \: E°_{cell} = \dfrac{2.303RT}{nF}\log(k_{c})

 \\

Kc= equilibrium constant at 298K

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Similar questions