Biology, asked by manjubijoy8571, 1 year ago

Net atp molecules produced, when glucose-6-phosphate undergoes complete oxidation in kidney cells are

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Answered by ancyvarghese
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Answer:

Glycolysis is a metabolic process in most organisms. It is the first stage in cellular respiration. It allows both aerobic and anaerobic respiration. Glycolysis releases only a small amount of energy.

Preparatory phase

The first half of glycolysis is the preparatory phase. It starts off by adding a phosphate group to glucose (Glucose 6-phosphate). Next the Glucose 6-phosphate is converted into Fructose 6-phosphate. Another phosphate group is added turning it into fructose -1,6- biphosphate. The fructose -1,6-biphosphate is then split in two, one part turning into G3P (Glyceraldehyde-3-phosphate) and dihydroxyacetone phosphate. The dihydroxyacetone phoshate is converted into G3P, leaving us with the two G3P triose sugar molecules used in the Pay-off phase.  

Pay-off phase

The second half of glycolysis is known as the 'pay-off phase', by the net gain of the energy-rich molecules ATP and NADH. Since glucose leads to two triose (G3P) sugars in the preparatory phase, each reaction in the pay-off phase occurs twice per glucose molecule. This yields 2 NADH molecules and 4 ATP molecules, leading to a net gain of 2 NADH molecules and 2 ATP molecules from the glycolytic pathway per glucose molecule.  

Summary: 2ATP → 4ATP + 2(NADH + H+) + 2 pyruvate (net production of 2ATP)

Explanation:

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