Physics, asked by maddularani17, 3 months ago

net distance formula​

Answers

Answered by archishman84
0

Answer:

Solution. Distance =∫102v(t)dt. ∫102v(t)dt=∫1/202v(t)dt+∫11/22v(t)dt=∫1/202(20t+5)dt+∫11/32(15)dt=∫1/20(40t+10)dt+∫11/230dt=[20t2+10t]|1/20+[30t]|11/2=(204+5)−0+(30−15)=25.

Explanation:

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