Question

Net muscle protein balance is the difference between muscle protein breakdown minus muscle protein synthesis muscle protein synthesis minus muscle protein breakdown muscle protein absorption minus muscle protein breakdown muscle protein synthesis minus muscle protein absorption​

Answer 1

Explanation:

To Find

How many moles of potassium chlorate is to be heated to produce 11.2 litre oxygen

Solution

We know that

At NTP (Normal Temp. & Pressure)

22.4 L of oxygen = 1 mole

Given that

11.2 L of oxygen

Mathematically

\sf 22.4 \ L \longrightarrow 1 \ mole22.4 L⟶1 mole

\sf 11.2 \ L \longrightarrow "x" \ moles11.2 L⟶"x" moles

Calculating

Moles of oxygen (x)

By cross multiplication

We get

\sf \longrightarrow x= \dfrac{11.2}{22.4}=\dfrac{1}{2} \ moles⟶x=

22.4

11.2

=

2

1

moles

Therefore

11.2 L of oxygen = 0.5 moles

Chemical equation

\sf 2KClO_{3} \xrightarrow{\Delta} 2KCl+3O_{2}2KClO

3

Δ

2KCl+3O

2

From the chemical equation

We can understand that

2 moles of potassium chlorate on heating gives 3 moles of oxygen

According to the question

We are asked to find how many moles of potassium chlorate is to be heated to produce 11.2 litre oxygen

We found out that

11.2 L of oxygen = 0.5 mole

Mathematically

\sf 3 \ moles \ of \ O_{2} \longrightarrow 2 \ moles \ of \ KClO_{3}3 moles of O

2

⟶2 moles of KClO

3

\sf 0.5 \ moles \ of \ O_{2} \longrightarrow "y" \ moles \ of \ KClO_{3}0.5 moles of O

2

⟶"y" moles of KClO

3

Calculating

Moles of potassium chlorate (y)

By cross multiplication

We get

\sf \longrightarrow y= 0.5 \times \dfrac{2}{3} = \dfrac{1}{3} \ moles⟶y=0.5×

3

2

=

3

1

moles

Therefore

1/3 moles of potassium chlorate is to be heated to produce 11.2 L of oxygen

Hence

Option (b) is correct