network of resistors R1 and R2 extends off to infinity to the right the equivalent resistance
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Consider the problem
R=2+2+2+R2×R⇒2R+R2=8+4R+2R⇒R2−4R−8=0⇒R=24±16+32=2±23
R can not be negative, Therefore
R=2+23=5.46Ω
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