Neutralisation happens when an acid and a base reacted together. Calculate the mass
of sodium hydroxide, NaOH that is needed to neutralise 250cm3
of 0.5M of nitric
acid
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Answer:
Answer:
5g NaOH
Explanation:
Required Neutralization Reaction :
NaOH + HNO3 ----> NaNO3 + H2O
We have to neutralize 250 cm³ of 0.5 M HNO3
Molaritly (M) = no. of moles of solute(n) x 1000/ vol of soln in cm³
0.5 (nx1000)/ 250 =
125 = n x 1000
n = 125/1000
n = 0.125 moles of HNO3
According to the reaction 1 mole of NaOH neutralize 1 mole of HNO3
• 1 mole of HNO3 is neutralized by = 1 mole of NaOH
mole of NaOH
0. 125 moles of HNO3 neutralized by =
0.125 moles of NaOH.
1 mole of NaOH has its mass equal to the Gram molecular weight (GMM) of NaOH.
1 GMM of NaOH = 23 + 16 + 1
= 40 g
•°• O. 125 moles of NaOH weigh = 40 × 0.
125
= 5 g
Therefore, 5g of NaOH is required to neutralize 250cm³ of 0.5M of nitric acid.
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