Question

Neva bought 1600 bananas at ₹3.75 a dozen. She sold 900 of them at 2 ₹1 And the remaining at ₹5 for ₹2 . Find her gain or loss percent

Answer 1

Answer:

Her gain percent is 46%

Step by step explanation:

Given:

• Neva bought 1600 bananas at ₹3.75 a dozen. ............ ( 1 dozen = 12)
• She sold 900 of them at 2 for ₹ 1
• And remaining bananas at ₹ 5 for 2

To find : Neva's gain or loss percent

★Solution :

$\large\implies{\sf }$Cost price of 12 bananas= ₹3.75

Therefore, Cost price of one banana= 3.75/12

$\large\implies{\sf }$ Cost price of 1600 bananas = 1600 x 3.75 / 12

$\large\implies{\sf }$ 1600 x 375 /12 x 100

$\large\implies{\sf }$ Cost price of 1600 banana = ₹ 500

→Now according to the question

Selling price of 900 bananas at 2 for ₹ 1 and remaining at ₹5 for 2

★Therefore, In case ....(1)

$\large\implies{\sf }$ Selling price of 900 bananas= 900/2 = ₹ 450..........(1)

∴ Remaining bananas= (Total bananas – Sold bananas) = (1600–900) = 700

★and , In case .......(2)

$\large\implies{\sf }$ Selling price of 700 bananas = 700 x 2 / 5

$\large\implies{\sf }$ 140 x 2 = ₹ 280..........(2)

★From equation (1) and (2), We got total Selling price of bananas = ₹ (450+280) = ₹730

→As we know that if S.P is greater than C.P then there is a profit ←

∴Profit = ( S.P – C.P)

$\large\implies{\sf }$ ₹(730–500) = ₹ 230

∴ Profit % = (Profit / C.P x 100)%

$\large\implies{\sf }$ (230 /500 x 100)%

$\large\implies{\sf }$ (230/5)% = 46 % .

★Hence , She got 46% profit on the whole transaction★

Answer 2

Her gain percent is 46%

Step by step explanation:

Given:

Neva bought 1600 bananas at ₹3.75 a dozen. ............ ( 1 dozen = 12)

She sold 900 of them at 2 for ₹ 1

And remaining bananas at ₹ 5 for 2

To find : Neva's gain or loss percent

★Solution :

\large\implies{\sf }⟹ Cost price of 12 bananas= ₹3.75

Therefore, Cost price of one banana= 3.75/12

\large\implies{\sf }⟹ Cost price of 1600 bananas = 1600 x 3.75 / 12

\large\implies{\sf }⟹ 1600 x 375 /12 x 100

\large\implies{\sf }⟹ Cost price of 1600 banana = ₹ 500

→Now according to the question

Selling price of 900 bananas at 2 for ₹ 1 and remaining at ₹5 for 2

★Therefore, In case ....(1)

\large\implies{\sf }⟹ Selling price of 900 bananas= 900/2 = ₹ 450..........(1)

∴ Remaining bananas= (Total bananas – Sold bananas) = (1600–900) = 700

★and , In case .......(2)

\large\implies{\sf }⟹ Selling price of 700 bananas = 700 x 2 / 5

\large\implies{\sf }⟹ 140 x 2 = ₹ 280..........(2)

★From equation (1) and (2), We got total Selling price of bananas = ₹ (450+280) = ₹730

→As we know that if S.P is greater than C.P then there is a profit ←

∴Profit = ( S.P – C.P)

\large\implies{\sf }⟹ ₹(730–500) = ₹ 230

∴ Profit % = (Profit / C.P x 100)%

\large\implies{\sf }⟹ (230 /500 x 100)%

\large\implies{\sf }⟹ (230/5)% = 46 % .

★Hence , She got 46% profit on the whole transaction★