Question

NeW QueStIon :

Two years ago a father has five times as old as his son. two years later, his age will be 8 year more than three times the age of son. find the present age of father and son?

Answer 1

Answer:

age of father=42years

age of son=10years

Step-by-step explanation:

let father age be x, son age be y

A. T. Q,

x-2=5(y-2)

=>x-2=5y-10

=>y=(x-2+10)/5=(x+8)/5......(1)

also,

x+2=3(y+2)+8

=>x+2=3y+14

=>x+2-14=3y

=>x-12=3y......(2)

putting (1)into(2),

x-12=3×(x+8)/5

=>x-12=(3x+24)/5

=>5(x-12)=3x+24

=>5x-60=3x+24

=>5x-3x=60+24

=>2x=84

=>x=84/2=42years

=>y=42+8/5=50/5=10years

Hope it helps you.

PLEASE MARK AS BRAINLIEST....

Answer 2

Given,

• Two years ago a father has five times as old as his son.
• Two years later father age will be 8 years more than three times the age of son .

To Find,

• The present age of father and son

Solution,

⇒Suppose the present age of son be "a"

And, Suppose the present age of his father be "b"

Now Given that : Two years ago

∴ Son's age =  (a - 2)

Father's age = (b -2)

$\boxed{\bold{\red{According \ to \ Question :}}}$

$\implies \sf{b - 2 = 5(a - 2)}$

$\implies \sf{b - 2 = 5a - 10}$

$\implies \sf{ b = 5a - 10 + 2}$

$\implies \boxed{\sf{b = 5a - 8}}$......1) Equation

Now Given that : Two years later

∴ Son's age = a +2

Father's age = b + 2

$\boxed{\bold{\red{ Again, According \ to \ the \ Question :}}}$

$\implies \sf{b + 2 = 8 + 3(a + 2)}$

$\implies \sf{ b + 2 = 8 + 3a + 6 }$

$\implies \sf{b + 2 = 3a + 14}$

$\implies \sf{b - 3a = 14 - 2}$

$\implies \sf{ b - 3a= 12}$

From First Equation :-

$\implies \sf{5a - 8 - 3a = 12}$

$\implies \sf{2a = 12 + 8}$

$\implies \sf{2a = 20}$

$\implies \sf{ a = \dfrac{20}{2}}$

$\implies \boxed{\sf{ a = 10 }}$

Now put the value of a in first Equation :-

$\implies \sf{ b = 5(10) - 8}$

$\implies \sf{b = 50 - 8}$

$\implies \boxed{\sf{ b = 42 }}$

Therefore ,

$\boxed{\bold{\red{ Son's \ age = a \ years = 10 \ years}}}$

$\boxed{\bold{\red{ Father's \ age = b \ years = 42 \ years}}}$

$\rule{200}2$