new syllabus methametics book 1 answers
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p(x) = 2x3 – 2x2 + ax – a
Divisor = x – a
∴ take x = a
By remainder theorem,
Remainder = p(a)
p(x) = 2x3 – 2x2 + ax – a
∴ p(a) = 2a3 – 2a2 + a(a) – a
= 2a3 – 2a2 + a2 – a
∴ Remainder = 2a3 – a2 – a
Answered by
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p(x) = 2x3 – 2x2 + ax – a
Divisor = x – a
∴ take x = a
By remainder theorem,
Remainder = p(a)
p(x) = 2x3 – 2x2 + ax – a
∴ p(a) = 2a3 – 2a2 + a(a) – a
= 2a3 – 2a2 + a2 – a
∴ Remainder = 2a3 – a2 – a
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