Question

New to congruence need answer for the below question

Answer 1

Answer:

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Answer 2

Answer:

1. in triangle SOQ and triangle POR

SQ = PR ( given )

OQ = OR (given )

angle QOS = angle ROP ( vertically opp. angles )

so triangle SOQ = triangle POR

now adding triangle QOR on both sides

∆SQO + ∆QOR = ∆ POR+ ∆ QOR

∆ SQR = ∆ PRQ

hence proved

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