Question

Newton's laws of motion formulation with formula​

Answer 1

Explanation :-

The laws of motion are as follows:

Newton’s First Law of Motion also known as Law of Inertia states that every object persists to stay in uniform motion in a straight line or in the state of rest unless an external force acts upon it.

Newton’s Second Law of Motion states that force is equal to the change in momentum per change in time. For a constant mass, force equals mass times acceleration, i.e. F = m*a.

Newton’s Third Law of Motion states that for every action there is an equal and opposite reaction.

Let us consider an object of mass m, moving along a straight line with an initial velocity u. Let us say, after a certain time t, with a constant acceleration, the final velocity becomes v. Here we see that, the initial momentum

$(p1) = m \times u$

The final momentum

$(p2) = m \times v$

The change in momentum can be written as

$p2 - p1 = (mv - mu) = m(v - u)$

As we know, the rate of change of momentum with respect to time is proportional to the applied force. The applied force

$f \: \: \alpha \: \: (m \times (v - u)) \div t$

Or,

$f \: \: \alpha \: \: m \times a$

as acceleration (a) = rate of change of velocity with respect to time.

$f = m \times k \times a$

Above is the second law of motion formula.

Notations Used In The Formula

F is the force

k is the constant of proportionality

a is the acceleration

HOPE THIS HELPS ❤️

Answer 2

Explanation :-

The laws of motion are as follows:

Newton’s First Law of Motion

 also known as Law of Inertia states that every object persists to stay in uniform motion in a straight line or in the state of rest unless an external force acts upon it.

Newton’s Second Law of Motion;

 states that force is equal to the change in momentum per change in time. For a constant mass, force equals mass times acceleration,

i.e. F = m*a.

Newton’s Third Law of Motion;

 states that for every action there is an equal and opposite reaction.

Let us consider an object of mass m, moving along a straight line with an initial velocity u. Let us say, after a certain time t, with a constant acceleration, the final velocity becomes v. Here we see that, the initial momentum

(p1) = m \times u(p1)=m×u

The final momentum

(p2) = m \times v(p2)=m×v

The change in momentum can be written as

p2 - p1 = (mv - mu) = m(v - u)p2−p1=(mv−mu)=m(v−u)

As we know, the rate of change of momentum with respect to time is proportional to the applied force. The applied force

f alpha (m \times (v - u)) \div tfα(m×(v−u))÷t

Or,

f alpha m \times afαm×a

as acceleration (a) = rate of change of velocity with respect to time.

f = m \times k \times af=m×k×a

Above is the second law of motion formula.

Notations Used In The Formula

F is the force

k is the constant of proportionality

a is the acceleration

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