Question

Newtonian mechanics demonstrates that the displacement of an object in free fall is given by the

relation s = ut + 1

2

at², where s is the displacement, u is the initial velocity, a is the acceleration, and t is the

time. This displacement equation is a polynomial expression. Polynomials enable people to describe the

physical world.

i. For example, assume that a ball is released from rest at the top of a building measuring 8.52 meters

tall. How long does it take for that ball to reach the ground?

(a) 1.23 seconds (b) 9.8 seconds (c) 1.32 seconds (d) 32 minutes​

Answer 1

Answer:

Correct option is

B

e

1

+2e

2

From the relation: h=ut+

2

1

gt

2

h=

2

1

gt

2

⇒g=

t

2

2h

(∵ body initially at rest)

Taking natural logarithm on both sides, we get:

lng=lnh−2lnt

Differentiating,

g

Δg

=

h

Δh

−2

t

Δt

For maximum permissible error:

(

g

Δg

×100)=(

h

Δh

×100)+2×(

t

Δt

×100)

According to problem:

h

Δh

×100=e

1

and

t

Δt

×100=e

2

Therefore, (

g

Δg

×100)=e

1

+2e

2

Step-by-step explanation:

please Mark me Brainlylest

Answer 2

Answer:

If a ball is released from a building top that measures 8.52 meters, then it takes 1.32 seconds to reach the ground

Step-by-step explanation:

Given the equation

$s=ut+\frac{1}{2}at^{2}$

Here,

s= 8.52 meters

The initial velocity u of freely falling body is 0 m/s

That is, u = 0 m/s

acceleration due to gravity is acting on a freely falling body so, a= 9.8 m/$s^{2}$

So, substituting values in the equation,

$s=ut+\frac{1}{2}at^{2}$ is,

$8.52 = 0+ \frac{1}{2}(9.8)*t^{2}$

$8.52 = 0+ 4.9*t^{2}$

$\frac{8.52}{4.9} = t^{2}$

$t^{2}=1.73877551$

t= √1.73877551

t =1.31862637

On rounding, we get 1.32 seconds

So, the time taken is 1.32 seconds