Question

Next, copy in your strip_punctuation function and define a function called get_pos which takes one parameter, a string which represents one or more sentences, and calculates how many words in the string are considered positive words. Use the list, positive_words to determine what words will count as positive. The function should return a positive integer - how many occurrences there are of positive words in the text. Note that all of the words in positive_words are lower cased, so you’ll need to convert all the words in the input string to lower case as well.

Answer 1

Answer:

ohh........... can't understand your question

Explanation:

sorry if you think bad

Answer 2

Language using: Python Programming

Program:

positive_words=['happy', 'strong', 'brainly', 'peace', 'well']

count=0

def strip_punctuation():

       x=input().lower()

       punctuations = '''!()-[]{};:'"\,<>./?@#$%^&*_~'''

       for i in x:

               if i in punctuations:

                       x=x.replace(i,"")

       return get_pos(x)

def get_pos(x):

       x=list(x.split(' '))

       global count

       for i in x:

               if i in positive_words:

                       count=count+1

       return count

print(strip_punctuation())

       

Input:

Hey, dear strong girl! Hope you are doing well, and leading a happy life that is filled with full of peace. Thank you for joining brainly. Brainly is happy to have you aboard. See you soon happy face!  

Output:

8

Learn more:

1) Printing all the palindromes formed by a palindrome word.

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2) Write a Python function sumsquare(l) that takes a nonempty list of integers and returns a list [odd,even], where odd is the sum of squares all the odd numbers in l and even is the sum of squares of all the even numbers in l.

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