Next door to me live four brothers of different heights. Their average height is 74 inches, and the difference in heipht among the first three men is two inches/'The difference between the third and the fourth man is six inches. Can you tell how tall is each brother? plzzzz ans will mark you as brainlist
Answers
Step-by-step explanation:
1 st - 70 Inches
2 rd - 72 Inches
3 rd - 74 Inches
4 th - 80 Inches
let 1 st be a , 2nd be b , 3rd be c ,&4th be d
a = a
b = a + 2
c = b + 2 = a + 2 + 2
d = c + 6 = a+2+6
thus,
74=(a+b+c+d)/4
74=(a+a+2+a+2+a+2+2+2+6)/4
74=(4a+16)/4
74=a+4
a=70
Thus,
b=a+2=70+2=72
c=a+2+2+2=70+2+2=74
d=a+2+2+6=70+2+2+6=80
Given,
Average heights of four brothers= 74 inches
The difference in height of the first three men= 2 inches
Difference between third and fourth man=6 inches
To find,
The heights of each brother among the four brothers
Solution,
We can solve this problem by following the steps below
Let the height of the first man A who is shortest among them be 'x'.
Let A, B, C, and D be their names respectively.
Average heights of A, B, C, and D=
= 74 inches
A= x
B= A+2 = x+2
C= B+2 = x+2+2=x+4
D= C+6 =x+2+2+6 = x+10
=
= =74 inches
4x+16 = 74 × 4
4x +16= 296
4x= 296-16
= 280
x = 280÷4
= 70 inches
A= x = 70
B= x+2 = 70+2=72
C= x+4 = 70+4= 74
D= x+10= 70+10=80
(Note: Average height in this problem is calculated by the Sum of the heights of all divided by the total number of persons whose average height is calculated.
Or in other words, Average= Sum value ÷ Number)
Thus, the heights of the four brothers who live next to me have their actual heights from the short to the tallest are 70, 72, 74, 80 inches.