Question

NH, gas can be prepared by heating together two solids NH,Cl and Ca(OH),. If
nixture containing 100 g of each solid is heated then
(a) Calculate the number of grams of NH, produced.
(b) Calculate the excess amount of reagent left unreacted.
2NH,Cl(s) + Ca (OH),(s) → CaCl (s) + 2NH2(g) + 2H2O(1)​

Answer 1

Answer:

The corresponding balanced chemical equation is as follows.

Ca(OH)2 +2 NH4Cl -> CaCl2 + 2 NH3 + 2H2O.

Thus 1 mole of Ca(OH)2 requires 2 moles of NH4Cl.

number of moles of in 100 g of each of reactants is

for Ca(OH)2 100 g / 74g mol^-1 = 1.35 moles

for NH4Cl. 100 g÷ 53.5 g mol^-1= 1.87 moles

In this case, NH4Cl is a limiting reagent

1.87 moles of it will react with 1.35/2= 0.675 moles of Ca(OH)2 producing 1.35 moles of NH3 i.e. 34 g × 1.35 =45.9 g of it.

Since 1 mole of any gas occupies 22.4 L

1.35 × 22.4 L corresponds to 30.24 L .