Chemistry, asked by jdbhabhor123, 2 months ago

NH2CN (s) + 3 / 2O2 (g) gives N2 (g) + CO2 (g) + H2O (l) bombs occur in calorimeters. The heat emitted from it is 743 KJ / mol. So what will be the value of ∆H300k for this process?​

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Answered by bannybannyavvari
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Answer:

The reaction NH2CN (s) + 3/2O2 (g) + CO2 (g) + H2O (l) was carried out at 300 K in a bomb calorimeter. The heat released was 743 kJ mol^-1 . The ...

NH2CN(s) + 32O2(g)→N2(g) + CO2(g) + H2O(l) Heat released = - 743kJ/mol H300K = ? H = U + ngRT U = change in internal energy ng = change in number of ... More

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