NH3 + (2)CuO -----> (3) Cu + (4) H2O + N2
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Answer:
The given reaction is as follows.
CuO + NH_{3} \rightarrow Cu + N_{2} + H_{2}OCuO+NH
3
→Cu+N
2
+H
2
O
Hence, oxidation state of the reactant atoms are as follows.
Cu = +2, O = -2, N = -3, H = +1
Oxidation state of the product atoms are as follows.
Cu = 0, N_{2}N
2
= 0, H = +1, O = -2
Therefore, balancing the given equation by oxidation method is as follows.
3CuO + 2NH_{3} \rightarrow 3Cu + N_{2} + 3H_{2}O3CuO+2NH
3
→3Cu+N
2
+3H
2
O
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