Question

NH3 + H2O + CO2 = NH4HCO3 - How many H- atoms were present in the reaction?

Answer 1

total 10 hydrogen atoms are present in this equation...but if we will se on reactant side there r 5 and product side there are also 5...

hope this may help u...❣

Answer 2

$NH_{3}+H_{2}O+CO_{2}\implies NH_{4}HCO_{3}$

The number of H-atoms starting the reaction was 3 + 2 = 5

The number of H-atoms formed from it = 4 + 1 = 5

But the number of H-atoms is formed from the original reactants

The number of H-atoms will be 5 obeying the Law of Conservation of mass and energy.

But if you ask how many H-atoms are present in both reactants and products,then the answer is 5+5 = 10

The appropriate answer I think should be 10

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