NH3 has greater dipolemoment than NF3. why?
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we know , in symmetrical structure dipolemoment is zero , because all charges cancelled each other .
now, see structure NH3 , and find out lone pair .
e.g no of lone pair = 1
we know, if any molecule have lone pair , it means this molecule isn't symmetry .e.g dipope moment isn't zero.
now, see structure of NF3 , and lone pair =1 , hence, this is symmetry. so, it's dipole moment isn't zero.
but according to VESPER theory, if any atom surrounded by more electronegative atoms then bigger bond angle , hence less dipole moment.
here in NF3 , N is surrounded by F and in NH3 , N is surrounded by H.F is more electronegative elements then H
so, NH3 has greater dipole moment then NF3
now, see structure NH3 , and find out lone pair .
e.g no of lone pair = 1
we know, if any molecule have lone pair , it means this molecule isn't symmetry .e.g dipope moment isn't zero.
now, see structure of NF3 , and lone pair =1 , hence, this is symmetry. so, it's dipole moment isn't zero.
but according to VESPER theory, if any atom surrounded by more electronegative atoms then bigger bond angle , hence less dipole moment.
here in NF3 , N is surrounded by F and in NH3 , N is surrounded by H.F is more electronegative elements then H
so, NH3 has greater dipole moment then NF3
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Answer:
In NH3 the orbital dipol due to lone pair and resultant dipol momentum os N-H bonds are in he same direction.
IN Nf3 orbitals dipole down to lone pair and the resut dipole moment of N-F bonds are in oppositr direction.
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