Ni(s) + 2Ag+ (aq) → Ni2+ (aq) + 2Ag(s)
For the above reaction depict the cell, individual half reactions and predict which one is cathiode and anode
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For the given reaction, Ni(s) + 2Ag+ (aq) → Ni2+ (aq) + 2Ag(s), the individual half cell reactions will be-
- Ni → Ni²⁺ + 2e⁻ (Oxidation half reaction)
- Ag⁺ + e⁻ → Ag (Reduction half reaction)
The standard electrode potential of Ni/Ni²⁺ is 0.236Vwhile that of Ag⁺/Ag is 0.8V.
So, when nickel and silver electrodes are taken, silver will act as the as cathode and nickel will be the anode.
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