Question

Nicholas buys 3/8 pound of cheese he put the same amount of cheese and three sandwiches how much cheese does Nicholas put on each sandwich

Answer 1

Total amount of cheese
$= \frac{3}{8} \: pounds$

Number of sandwiches = 3
Amount of cheese he put on 1 sandwich
$= \frac{3}{8} \div 3 \\ = \frac{3}{8} \times \frac{1}{3}$
3 and 3 will get cancelled
So the amount of cheese he put on 1 sandwich
$= \frac{1}{8} \: pounds$

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Answer 2

Given:

(i) Nicholas buys 3/8 pound of cheese.

(ii) He puts the same amount of cheese in three sandwiches.

To find:

(i) The amount of cheese he puts in each sandwich.

Solution:

It is given that Nicholas puts $\frac{3}{8}$ pounds of cheese in 3 sandwiches.

The amount of cheese he puts in each sandwich would obviously be lesser.

In 3 sandwiches,  $\frac{3}{8}$ pounds of cheese are put.

So, by unitary method, in 1 sandwhich, $\frac{3}{(8*3)}$ = $\frac{1}{8}$ pounds of cheese are put.

Therefore, Nicholas puts $\frac{1}{8}$ pounds of cheese in each sandwich.