Question

Nichrome resistance coil of 25 om is connected with 12 volt accumulator cell (Battery) and current flows through it for 15 minutes. Determine heat produced in this coil.

Answer 1

Heat ,H =
${i}^{2} rt$
or we can write H =
${v}^{2} t \div r$

as V=IR
therefore
just enter values and find out the answer

Answer 2

The heat produced in the coil is 5184 J.

Explanation:

The heat produced by an electric current, i through a coil of resistance, R for a time, t is given by.

$H = i^2Rt$

We know,

voltage V =iR   (Ohm`s law)

So above formula becomes,

$H=\frac{V^2}{R} t$

Given  V = 12 V, R =25 ohm and t = 15 min.

Substitute the value, we get

$H=\frac{(12)^2}{25}\times15\times60s$

H = 5184 J.

Thus, the heat produced in the coil is 5184 J.

#Learn More:  Heat produced in conductor.

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