nichrome wire of length 1 and radius R has resistance of 10 ohm how would the resistance of the wire change when i) only length of wire doubled ii) only diameter of the wire is doubled?
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Explanation:
R ∝ L So resistance becomes two times i.e., R = 20 Ω
(ii) R ∝ 1/A ∝ 1/d2 So when the diameter is doubled, resistance becomes one-fourth of the original i.e., R =2.5 Ω
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