Question

Nick draws water from a well having depth of 5m. Calculate the maximum weight of water he can pull up if the maximum work he is capable of doing is 100 J and he is using a rope to lift the water which can bear a maximum load of

Answer 1

Answer :-

• Maximum Weight of Water = 18 N

Given :-

• Depth of Well (Here Displacement) = 5 m
• Work Done = 100 J
• Gravity = 10 m/s²

To Find :-

• Maximum Weight of Water = ?

Explanation :-

This question is not a numerical question, thus we will solve it easily :)

As above given,

Nick is using a rope for drawing the water that can bear a load of '18 N'.

When Nicks pulls the rope with water from well then the maximum weight of water is also '18 N'

Reason :-

Since the rope can bear the maximum weight of 18 N therefore maximum weight of water that can pulled is 18 N.

Hence, the Maximum Weight (Here Mass) that Nick can be pull from the well is 18 N.      

$\bf \Large \text { \underline {\underline{More To Know}}}$  

$\rm \blacksquare \: W = F \times S \qquad S.I \: Unit \rightarrow \bold{Joule\:(J)}$  

$\rm \blacksquare \: F = M \times A \qquad S.I \: Unit \rightarrow \bold{Newton \: (N)}$  

$\rm \blacksquare \: S = V \times T \qquad S.I \: Unit \rightarrow \bold{Meter \: (m)}$  

$\rm \blacksquare \: K_E = \dfrac{1}{2}mv^2 \qquad S.I \: Unit \rightarrow \bold{Joule \: (J)}$  

$\rm \blacksquare \: P_E = mgh \qquad S.I \: Unit \rightarrow \bold{Joule \: (J)}$  

$\rm Symbols \: Meaning \implies \begin{cases} \odot \: {\bf m} = Mass \\ \odot \: {\bf s} = Displacement \\ \odot \: {\bf f} = Force \\ \odot \: {\bf a,g} = Acceleration,Gravity \\ \odot \: {\bf w} = Work \: Done \\ \odot \: {\bf t} = Time \\ \odot \: {\bf v} = Speed \\ \odot \: {\bf K_E} = Kinetic \: Energy \\ \odot \: {\bf P_E} = Potential \: Energy \end{cases}$  

Answer 2

Given:

Nick draws water from a well having depth of 5m. The maximum work he is capable of doing is 100 J and he is using a rope to lift the water which can bear a maximum load of 18N.

To find:

Calculate the maximum weight of water he can pull up.

Solution:

Work done by Nick = Work done by water + Work done by rope

W = Mgh + mgh

where M is the weight of water

m is the weight lifted by rope

h is the height of the well

Substitute the values in the above equation.

100 = M × 9.8 × 5 + 18 × 9.8 × 5

100 = 49  M + 882

49 M = 100 - 882

M = - 782/49

M =  - 15.95 N (in opposite direction to that of the earth's gravitational force)

M ≈ 16 N

Therefore, the maximum weight of water Nick can pull up is 16 N.