Math, asked by naeem140575, 1 year ago

Nick has a 50-foot ladder. He places the ladder 20 feet away from the base of a building.

What is the distance between the base of the building and the top of the ladder, x, to the nearest foot?















Answers

Answered by vijayakeshavbhat
1

Answer:

√2100=45.8 is the distance

Answered by kingofself
1

Answer:

The distance between the base of the building and the top of the ladder, x, to the nearest foot is 43.

Step-by-step explanation:

Given:

Nick has a 50-foot ladder. He places the ladder 20 feet away from the base of a building.

To find:

What is the distance between the base of the building and the top of the ladder, x, to the nearest foot?

Solution:

Consider the given situation in right angled triangle,  

By pythogoras theorem,  

X^2 + 20^2 =  50^2

X^2 = 2100

x = 43 (approx)

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