Niharika got 90% marks in Science, 80% marks in Hindi 72% marks in English,
00% marks in Mathematics and 95% marks in Social Science, If each subject
carries 100 marks, then find the percentage of marks obtained by Niharika in the
aggregate of all the subjects. Also depict the characteristics of Niharika
Answers
GIVEN :-
- Each subject carries 100 marks.
- Niharika got 90% marks in Science, 80% marks in Hindi 72% marks in English,
- 100% marks in Mathematics and 95% marks in Social Science.
TO FIND :-
- Percentage she got in overall subjects.
SOLUTION :-
Total marks = Total subjects × 100
Total marks = 5 × 100
Total marks = 500 marks
♦ For Science , she scored 90% of 100marks.
→ (90/100) × 100
→ 90 marks
♦ For Hindi , she scored 80% of 100 marks.
→ (80/100) × 100
→ 80 marks
♦ For English , she scored 72% of 100 marks.
→ (72/100) × 100
→ 72 marks
♦ For Mathematics , she scored 100% of 100 marks.
→ (100/100) × 100
→ 100 marks
♦ For Social Science , she got 95% of 100 marks.
→ (95/100) × 100
→ 95 marks
Hence ,
Obtained marks = 90 + 80 + 72 + 100 + 95
Obtained marks = 437 marks
% = (Obtained marks/Total marks) × 100
= (437/500) × 100
= 43700/500
= 87.4%
Hence , Niharika obtained 87.4% percent.
Given:-
Niharika got mark's :-
Science - 90%
Hindi - 80%
English - 72%
Mathematics - 100%
Social Science - 95%
★Each subject carries 100% mark's.
To find :-
Percentage of marks obtained by
Niharika in the aggregate of all the subjects.
=> Total marks = total subjects × 100
=> 5×100
=> 500, are total mark's.
☆ In science, She scored 90% of 100% mark's.
= [99/100]×100
90% mark's
☆ In hindi, She scored 80%" of 100% mark's.
= [80/100]×100
80%mark's
☆ In English, She scored 72% of 100% mark's.
= [72/100]×100
72% mark's
☆ In mathematics, She scored 100% of
100%mark's.
= [100/100]×100
100% mark's
☆In social science, She scored 95% of
100% mark's
= [95/100]×100
95% mark's
Hence,
Obtained mark's = 90 + 80 + 72 + 100 +95
Total obtained marks = 437% mark's.
%= [ obtained mark's / total mark's] × 100
= [437/500]×100
= 43700/500
=87.4%