Question

Nikhila walks 10 m in the South-east direction She then starts walking in the direction East and covers 25 m. At this point she turns North-west and walks 10 m. She then walks another 13 m in the West direction. Finally she turns right and walks 5 m. How far is he from the starting point?​

Answer 1

Answer:

Answer is 2 m from the point of his starting

Answer 2

Answer:

Nikhila is 13m NE from the starting point.

Step-by-step explanation:

let the starting point be O,

1. 10m to southeast ( O to A )

2. 25m to east         ( A to B )

3. 10m to northwest ( B to C )

4. 13m to west           ( C to D )

5. 5m to right             ( D to E )  E is in North-East position

1 and 3 are opposite and equal => displacement 1 = 0

2 and 4 are opposite and in same line => displacement = 25-13 = 12m E

5 is 5m to the right (North)

so finally we get a right triangle with base =  12m and height= 5m

=> the hypotenuse will be the total displacement

=> hyp = $\sqrt{base^2 + height^2}$  (as per pythagorous theorem)

            = $\sqrt{12^{2} + 5^{2} }$ m

            = $\sqrt{144+25} }$ m

            = $\sqrt{169 }m$

            = 13m

=> Nikhila is 13m NE from the starting point (see attachment)