nikki57 this is for u
question no. 3
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Final Answer :B:
Fx/2m √(a^2-x^2)
Steps and Understanding :
1) Vertical component of Tension is provided by Force F
So, 2T sin ¤ = F
2) Then, we will write horizontal motion equation of mass m.
Tcos¤ = ma.
3) Divide these both equations to get acceleration.
For Figure ,Calculation and geometry see pic.
Fx/2m √(a^2-x^2)
Steps and Understanding :
1) Vertical component of Tension is provided by Force F
So, 2T sin ¤ = F
2) Then, we will write horizontal motion equation of mass m.
Tcos¤ = ma.
3) Divide these both equations to get acceleration.
For Figure ,Calculation and geometry see pic.
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Answered by
2
Final Answer :B:
Fx/2m √(a^2-x^2)
Steps and Understanding :
1) Vertical component of Tension is provided by Force F
So, 2T sin ¤ = F
2) Then, we will write horizontal motion equation of mass m.
Tcos¤ = ma.
3) Divide these both equations to get acceleration.
Read more on Brainly.in - https://brainly.in/question/3614263#readmore
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