Question

nim
Maximize Z= 3X1 + 4X2

subject to
5X1 + 4X2 s 200
3X1 + 5X2 < 150
5X1 + 4X2 > 100
8X1 + 4X2 > 80
both
X1 , X2 > 0
using graphical method of Linear
Programming Problem.​

Answer 1

Answer:

) x1 = 2.5, x2 = 35 z = 3x1 + 4x2 Let us solve the equations 2x1 + x2 = 40 ... (1) 2x1 + 5x2 = 180 … (2) (1) – (2) ⇒ -4x2 = -140 x2 = 35 We have 2x1 + x2 = 40 2x1 + 35 = 40 2x1 = 5 x1 = 2.5Read more on Sarthaks.com - https://www.sarthaks.com/987730/maximize-3x1-4x2-subject-2x1-2x1-5x2-180-the-lpp-which-one-the-following-feasible-comer-point?show=987740#a987740