Question

Nimnalikhit ko HAL kijiye (2x+3y+4z)²

Answer 1

Step-by-step explanation:

${(2x+3y+4z)}^{2}$

=

${ (2x)}^{2} + {(3y)}^{2} + {(4z)}^{2} + 2(2x)(3y) + 2(3y)(4z) + 2(4z)(2x)$

=

$4 {x}^{2} + 9 {y}^{2} + 16 {z}^{2} + 12xy + 24yz + 16zx$

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