Question

nine added to the product of a 2 consecutive multiples of 6 gives 729 what are the numbers?​

Answer 1

Answer:

4 and 5

Step-by-step explanation:

Let 2 consecutive multiples be 6x and 6(x+1)

9+6x.6(x+1 )=729

36.x.x+1=729-9

x.x+1=720/36

x.x+1=20

The possible factors are (1,20) (2,10) (4,5)

The ANS is 4 and 5 (since, consecutive multiples)

Hope this helps you!

Answer 2

Answer:

24,30

Step-by-step:

Let the first multiple of 6 be x And second be (x+6)

ATP,

{x(x+6)}+9 = 729

{x(x+6)} = 729-9 = 720

Let x be 24 then,

(24)(24+6) = 720

24 * 30 = 720

So the no. Are 24 and 30