Math, asked by manjulapalamaku5265, 1 year ago

Nine days ago, the area covered by the mold on a piece of bread was 3 square inches. Today the mold covers 9 square inches. What is the rate of change in mold's area?

Answers

Answered by enyo
1

Answer: The rate of change in mold's area would be 2 square inches per day.


Step-by-step explanation:

Given that,

The area covered by mold 3 days ago= 3 square inches

The area covered by mold today= 9 square inches

Change in area= 9-3= 6 square inches

Number of days during which this change occured= 3

So,

The rate of change in mold's area= change in area/number of days

The rate of change in mold's area= 6/3=2 square inches per day.

Answered by hiteshgyanchandani6
0

The area covered by the mold nine days ago= 3 square inches.

The area covered by the mold in the present time= 9 square inches.

The change in area covered by mold is = 9-3=6 square inches

6 square inches change occurred in 9 days.

Now, The rate of change in mold’s area is Change in area covered / time taken.

The rate of change = 6/9

= 2/3

The rate of change in mold’s area is 2/3 square inches per day.

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