Nine element of which 4 are of one kind and 5
are of a
a different kind arranged in a sequence
If R is the number of runs. Probability (R=2)
is equal to :
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0
Answer:
I think this is the right answer
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Answered by
1
Answer:
1/63
Explanation:
no. of arrangement = 9!/4!5!
= 126
p(r=2) = 2/126
=1/63
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