CBSE BOARD XII, asked by zhxhcjvkvkv, 1 month ago

Nine element of which 4 are of one kind and 5
are of a
a different kind arranged in a sequence
If R is the number of runs. Probability (R=2)
is equal to :

Answers

Answered by shrutipr19

0

Answer:

I think this is the right answer

Attachments:

Answered by kumaridiksha910

1

Answer:

1/63

Explanation:

no. of arrangement = 9!/4!5!

= 126

p(r=2) = 2/126

=1/63

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