Question

nine subtracted from 6 times of a natural number gives its own square what is the number.​

Answer 1

Answer:

The number is 3.

Step-by-step explanation:

let the natural number be x.

we have,

6(x)-9=$x^{2}$

6x-9=$x^{2}$

0=$x^{2}$-6x+9

∴By Splitting middle term of this Quadratic Eq

0=$x^{2}$-3x-3x+9

0=x(x-3)-3(x-3)

∴The value of x=3

The natural number is 3

Lets prove it,

LHS,

6(3)-9=18-9= 9

RHS=$3^{2}$

=9

LHS=RHS

HENCE PROVED THAT THE NATURAL NUMBER IS 3.

Thank you..........