Question

Nine time a two digit number is the same as twice the number obtained byinterchanging the digits of the number if one digit of the number exceeds the other number by 7 find the numberenercomp ​

Answer 1

Answer:

99999999999999999999

Answer 2

Answer

18 is the number

Step-by-step explanation:

let the two digits of the number be y and x for unit and tens place respectively

according to first condition,

9[10x+y]=2[10y+x]

90x+9y=20y+2x

88x+9y=20y

88x+9y-20y=0

88x-11y=0

8x-y=0    -------[1]

according to second condition,

y-x=7-----[from first equation it is clear that y is greater than x]------[2]

adding [1] and [2] we get

  8x-y=0

[+]-x+y=7

----------------

7x=7

x=1

substituting the value of x in [2] we get,

y-x=7

y-1=7

y=7+1

y=8

the number=10x+y=[10*1]+8

=10+8

=18