Question

Nine times a two digit number is the same as twice the number obtained by interchanging the digits of the number if one digit of the number exceeds the other number by 7 find the number

Answer 1

Answer:

Ans=18

Step-by-step explanation:

Let 10th place=x

one's place=y

then Number=10x+y

Now the number after interchanging the digits

=x+10y

Given that

Now,

9*(two-digit number) = 2*(The number obtained by interchanging the digits)

Hence

9*(10x+y)=2*(x+10y)

90x+9y=2x+20y

90x-2x+9y-20y=0

88x-11y=0

8x-y=0

y=8x--------------(1)

===============================

Now one digit is 7 more than other

so y=x+7 --------------(2)

from(1) and (2)

8x=x+7

7x=7

x=1

Hence y=x+7=1+7=8

Therefore the number is:

10x+y=10*1+8=18

Ans=18

Answer 2

Answer:

Ans = 18.

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