Question

Nine times the first of the five consecutive odd integers is 7 more than four times the second

Answer 1

Step-by-step explanation:x,(x+2),(x+4),(x+6) & (x+8)

x+(x+8)=3(x+6)-1

x+x+8=3x+18-1

2x-3x=17-8

-x=9

x=-9 answer for the first number

 

-9+2=-7 second number

-9+4=-5 third number

-9+6=-3 fourth number

-9+8=-1 fifth number

proof

-9+(-1)=3*-3-1

-10=-9-1

-10=-10