Question

nine times the side of a square exceeds a perimeter of a second square by the one meter and six times the area of the second square exceeds 29 times the area of the first by one square metre. find the side of each square. ​

Answer 1

Answer:

Step-by-step explanation:

Hey dear,

● Answer-

s1 = 5

s2 = 11

● Explaintion-

# Given-

9s1 = p2 + 1

6A2 = 29A1 + 1

# Solution-

We have

9s1 = p2 + 1

9s1 = 4s2 + 1

s2 = (9s1-1)/4 ...(1)

Also,

6A2 = 29A1 + 1

6s2^2 = 29s1^2 + 1

Putting values,

6(9s1-1)^2/16 = 29s1^2 + 1

486s1^2 - 108s1 - 6 = 464s1^2 + 16

11s1^2 - 54s1 - 5 = 0 ...(2)

Solving (1) and (2),

s1 = 5

s2 = 11

Hope this is useful...

Read more on Brainly.in - https://brainly.in/question/7307958#readmore