Question

nine times the side of one square exceeds a perimeter of a second square by One meter and six times the area of the second square exceeds 29 times the area of the first by one square metre . find the side of each square​

Answer 1

Answer:

Step-by-step explanation:

● Answer-

s1 = 5

s2 = 11

● Explaintion-

# Given-

9s1 = p2 + 1

6A2 = 29A1 + 1

# Solution-

We have

9s1 = p2 + 1

9s1 = 4s2 + 1

s2 = (9s1-1)/4 ...(1)

Also,

6A2 = 29A1 + 1

6s2^2 = 29s1^2 + 1

Putting values,

6(9s1-1)^2/16 = 29s1^2 + 1

486s1^2 - 108s1 - 6 = 464s1^2 + 16

11s1^2 - 54s1 - 5 = 0 ...(2)

Solving (1) and (2),

s1 = 5

s2 = 11

Hope this is useful..