nine trends are standing in height order from the smallest on the left and tallest on the right the 5 trends from the left have an average height of 150 cm. the 5 trends from the right have an average height of 170cm. if the middle trend who is 160cm tall leaves then what is the average height of the remaining 8 trends?
Answers
Answer:
160
Step-by-step explanation:
9 friends : a,b,c,d,e,f,g,h,i
let assume a is on the left and i is on the right side.
So, (a+b+c+d+e)/5 =150 (Given)
and (e+f+g+h+i)/5= 170 (Given)
and e= 160
hence, a+b+c+d+160 = 150*5
a+b+c+d=750-160 = 590
Similarly,
160+f+g+h+i=170*5
f+g+h+i=850-160=690
Average of remaining 8 firend: ( (a+b+c+d)+(f+g+h+i)) /8
=> (590+690)/8 => 1280/8 => 160
Given: Nine trends are standing in height order from the smallest on the left and tallest on the right the 5 trends from the left have an average height of 150 cm. the 5 trends from the right have an average height of 170cm. The middle trend who is 160cm tall leaves.
To find: The average height of the remaining 8 trends.
Solution:
The average of a given set of values is given by dividing the sum of the values by the number of values. So, the average height of the 5 trends from the left and the 5 trends from the right can be written as follows.
Here, S₁ and S₂ are the sums of the heights of the 5 trends from the left and from the right, respectively. Now, when the middle trend of height 160 cm leaves, the given averages can be written as follows.
Now, the (S₁-160) represents the sum of the four trends from the left and (S₂-160) represents the sum of the four trends from the right. That makes a total of the remaining 8 trends. Thus, the average can be calculated as
Therefore, the average height of the remaining 8 trends is 160 cm.