nine y square minus six root two y plus two equal to zero
Answers
Answered by
1
Answer:
Roots of the given Quadratic equation are real and different.
Step-by-step explanation:
Given Quadratic Equation:
9x² - 6x - 2 = 0
To find: Nature of the roots of the Quadratic Equation.
We know that nature of the roots depend on the value of discriminant, D = b² - 4ac
If D > 0 then roots are real and different.
If D = 0 then roots are real and same.
If D < 0 then roots does not exist or say roots are complex conjugate or imaginary number.
here, a = 9 , b = -6 and c = -2
So, D = (-6)² - 4(9)(-2) = 36 + 72 = 108
Since, D > 0
⇒ Roots are Real and different.
Therefore, Roots of the given Quadratic equation are real and different.
Answered by
0
Answer:- Hii Friend Pls check the picture attached here
Necessary:- To mark me as brainliest and thanks me if you like my answer also vote me 5 star
Attachments:
Similar questions