Question

Nine years ago a woman was three times as old as her son . In eight years from now the sum of their ages will be 78 . How ald are they today

Answer 1

Answer:

50 and 28

Step-by-step explanation:

today woman is x, son is y

x-9=3(y-9)

x-9=3y-27

3y-x=18

in 8 years x+8 and y+8 and that sum is 78, so x+y+16=78

x+y=62

x=62-y

so 3y-62+y=18

4y=80

y=20 son

x=42 mother

nine years earlier it was 33 and 11

8 years from now it will be 50 and 28

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