Question

Ninety is divided into three unequal parts such that the sum of the first two parts exceeds the sum of the second and the third parts by 18

Answer 1

Answer:

Let us consider the division it would be x,y,z

Now

x+y=y+z+18(given)

x=z+18( let's us not run to the conclusion and say that z is 18)

x+y+z=90

x=z+18 (now there are two conclusions either y is the smaller part or z but not x)

Let us put first y as 18 and x as z+18

z+18+18+z=90

2z+36=90

2z=90-36

2z=54

z=27

So x = z+18

x=27+18

x=45

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