Question

Ninety three is divided into two parts such that thrice the first part and twice the second part are in the ratio 25:4. find the first part

Answer 1

hope u understand , space kam tha so answer side pe likh diya

Answer 2

Answer:

75

Step-by-step explanation:

Let the first part be x

Let the second part be y

Since we are given that Ninety three is divided into two parts

So, x+ y = 93  --1

Now we are given that thrice the first part and twice the second part are in the ratio 25:4.

$\frac{3x}{2y} =\frac{25}{4}$

$12x =50y$

$x =\frac{50}[12}y$

$x =\frac{50}[12}y$

Substitute value in 1

$\frac{50}{12} y+y =93$

$50y+12y =1116$

$62y =1116$

$y =\frac{1116}{62}$

$y =18$

So, second part si 18

So, x+18 =93

x = 93-18 = 75

Hence the first part is 75