ninth term of an AP is equal to Sevetimes the second term and twelfth term exceeds five times the third term by 2find the first term and (common difference
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put a = 1 in equation ( 1 ) , we get
d = 6
Therefore ,
first term = a = 1 ,
common difference = d = 6
I hope this helps you.
:)
d = 6
Therefore ,
first term = a = 1 ,
common difference = d = 6
I hope this helps you.
:)
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Answered by
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Hello..
Let us take common difference be a and d
A.T.Q
T9=7t2
A+8d=7a+7d
D=6a.. eq.1
T12 = 5t3 + 2
a+11d=5a+10d+2
d=4a+2
6a=4a+2(eq.1)
2a=2
a=2/2
A=1
Let us take common difference be a and d
A.T.Q
T9=7t2
A+8d=7a+7d
D=6a.. eq.1
T12 = 5t3 + 2
a+11d=5a+10d+2
d=4a+2
6a=4a+2(eq.1)
2a=2
a=2/2
A=1
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