niobium crystallises in body centred cubic structure.If density is 8.55g cm^-3 calculate atomic radius of niobium using its atomic mass 93*10^-6
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Answer:
14.29 nm
Explanation:
Atomic radius)^3 =Zeff × A.wt/( P×Na)
a^3= 2×94/ 8.55 ×6.02×(10)^23
a^3= 3.27× 10^(-23) cm^3
a=14.29 × 10^(-7) cm
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