Niobium crystallises in body-centred cubic structure. if density is 8.55 g cm–3, calculate atomic radius of niobium using its atomic mass 93 u.
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a^3=zM/dN°=2×93/8.55×6.022×10^23=36.12×10^24cm3 a=(36.12×10^24)^1/3=3.306×10^-10 m
r=✓3/4a =1.431.×10^-10m
r=✓3/4a =1.431.×10^-10m
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