Nisha scored 73,86,78 and 75 marks in four tests. What is the least number of marks she can score in her next test, if she has to have a mean score of 80 marks in five tests?
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Answered by
30
Nina has to score 88.
Lrt nina scores x in her next test. And x is the minimum marks. Now mean marks of nina is (73+75+78+86+x)/5=80. On solving this equation we get x is 88. Thus minimum marks in the next test is 88.
Lrt nina scores x in her next test. And x is the minimum marks. Now mean marks of nina is (73+75+78+86+x)/5=80. On solving this equation we get x is 88. Thus minimum marks in the next test is 88.
Answered by
74
Let Nisha scores 'x' marks in her 5th test so as to have a mean score of 80 marks in five tests.
So, according to the question.
(73 + 86 + 78 + 75 + x)/5 = 80
(312 + x)/5 = 80
312 + x = 400
x = 400 - 312
x = 88
So, Nisha has to score 88 marks in her 5th test so as to have a mean score of 80 marks in five tests.
So, according to the question.
(73 + 86 + 78 + 75 + x)/5 = 80
(312 + x)/5 = 80
312 + x = 400
x = 400 - 312
x = 88
So, Nisha has to score 88 marks in her 5th test so as to have a mean score of 80 marks in five tests.
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