Question

nisha walks 15m west and 8m north to reach tha apposite corner of a rectangular field .mary walked from the same point diagonally to the apposite corner what is the distance covered by mary

Answer 1

Firstly, let ABCD be the required rectangle.

Then, Nisha moves from A to B - 15 m and then B to C - 8 m

And, Mary walks from A to C. Then we have to find the distance between A and C.

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Now,

All the angles of a rectangle are 90°

=> angles A = B = C = D = 90°

Hence, in the fig.,

AB = 15 m

BC = 8 m

Angle B = 90°

Now, side opposite to 90° is called the hypotenuse

Hence, AC is the hypotenuse

That makes a right angled triangle ABC at angle B.

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Now, we use the Pythagoras' Theorem; which states that in a right angled triangle, the square of the hypotenuse is equal to the sum of square of other two sides, to solve the question.

AC² = AB² + BC²

=> AC² = 15² + 8²

=> AC² = 225 + 64

=> AC² = 289

=> AC = √289

=> AC = 17 m

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Hence, the distance covered by Mary = AC

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Answer 2

H=17m
so,
marry walk 17m